Mexico drawn in Group A of the 2019 CONCACAF U-15 Championship

Mexico will be try to defend their current crown of CONCACAF U-15 Champions after being drawn in Group A along with Panama, Trinidad and Tobago and Curaçao. The tournament will be held in Bradenton, Florida with all CONCACAF teams participating along with invited teams Slovenia, Portugal, and Israel. The tournament will be divided into three divisions, with Mexico being part of Division One along with 13 other CONCACAF teams, Portugal, and Slovenia. The top two teams in each group will qualify to the Quarterfinals.

Mexico comes into the tournament as the current champions after winning the 2017 tournament, defeating the United States by a score of 2-0. They will open the tournament on August 4th with their match against Panama. On August 5th, they will play their next game against Trinidad and Tobago. Finally on August 7th, they will close out their group play with their match against Curaçao.

Mexico recently won the Trinidad and Tobago Youth Tournament with 7 points, in which oddly enough they faced two of their group rivals. In that tournament, they won their opener against Venezuela (2-0) and then proceeded to face their future rivals Panama and Trinidad and Tobago. They tied against Panama (1-1) and then beat the hosts Trinidad and Tobago (4-1), clinching the title with seven points to Panama’s five points.